True, but the resistor is a 10k one. So 3.6V / 10k = 0.36mA. I would think this is too little to light a LED. I don't know the inner workings of the digital interface of the chip. My guess is that I somehow managed to damage it causing high current on this particular pin. I don't know if the high current is also there when the interface is enabled (low CSB). But at least when the interface is in high-z mode, there is excess current on the clock pin.
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